j^2-22j+21=0

Solution for j^2-22j+21=0 equation:

Simplifying
j2 + -22j + 21 = 0

Reorder the terms:
21 + -22j + j2 = 0

Solving
21 + -22j + j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(1 + -1j)(21 + -1j) = 0

Subproblem 1
Set the factor '(1 + -1j)' equal to zero and attempt to solve:

Simplifying
1 + -1j = 0

Solving
1 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1j = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1j = 0 + -1
-1j = 0 + -1

Combine like terms: 0 + -1 = -1
-1j = -1

Divide each side by '-1'.
j = 1

Simplifying
j = 1
Subproblem 2
Set the factor '(21 + -1j)' equal to zero and attempt to solve:

Simplifying
21 + -1j = 0

Solving
21 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-21' to each side of the equation.
21 + -21 + -1j = 0 + -21

Combine like terms: 21 + -21 = 0
0 + -1j = 0 + -21
-1j = 0 + -21

Combine like terms: 0 + -21 = -21
-1j = -21

Divide each side by '-1'.
j = 21

Simplifying
j = 21
Solution
j = {1, 21}